Minggu, 25 April 2010

Membuat Subnetting Class C Menjadi 4 Subnet


Subnet id 1 = 50 host

Subnet id 2 = 30 host

Subnet id 3 = 12 host

Subnet id 4 = 10 host

Jawab:

IP address : 192.168.0.6

Subnet Mask : 255.255.255.224

: 11111111.11111111.11111111.11100000

111 bit untuk menentukan jumlah subnet id

00000 bit untuk menentukan jumlah host

Jumlah subnet id : 23 = 8

Subnet id 1 : 192.168.0.00000000 (0)

Subnet id 2 : 192.168.0.00100000 (32)

Subnet id 3 : 192.168.0.01000000 (64)

Subnet id 4 : 192.168.0.01100000 (96)

Subnet id 5 : 192.168.0.10000000 (128)

Subnet id 6 : 192.168.0.10100000 (160)

Subnet id 7 : 192.168.0.11000000 (192)

Subnet id 8 : 192.168.0.11100000 (224)

Jumlah host : 25-2 = 30

1. Host pertama ——————> Host terakhir

192.168.0.1 30 host 192.168.0.30

Subnet : 192.168.0.0

Broadcast : 192.168.0.31

2. Host pertama ——————-> Host terakhir

192.168.0.33 30 host 192.168.0.62

Subnet : 192.168.0.32

Broadcast : 192.168.0.63

3. Host pertama ——————-> Host terakhir

192.168.0.65 30 host 192.168.0.94

Subnet : 192.168.0.64

Broadcast : 192.168.0.95

4. Host pertama ——————-> Host terakhir

192.168.0.97 30 host 192.168.0.126

Subnet : 192.168.0.96

Broadcast : 192.168.0.127

5. Host pertama ——————->Host terakhir

192.168.0.129 30 host 192.168.0.158

Subnet : 192.168.0.128

Broadcast : 192.168.0.159

6. Host pertama ——————-> Host terakhir

192.168.0.161 30 host 192.168.0.190

Subnet : 192.168.0.160

Broadcast : 192.168.0.191

7. Host pertama ——————-> Host terakhir

192.168.0.193 30 host 192.168.0.222

Subnet : 192.168.0.192

Broadcast : 192.168.0.221

8. Host pertama ——————->Host terakhir

192.168.0.225 30 host 192.168.0254

Subnet : 192.168.0.224

Broadcast : 192.168.0.255

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